Given that logb(7)≈1.946, logb(9)≈2.197, and logb(16)≈2.773, find the logarithm of logb(1/63)
b is base b

The logarithmic expression given as logₙ(1/63) has its value to be -4.143How to determine the logarithmic expression?From the question, the given parameters arelogₙ(7) = 1.946logₙ(9) = 2.197logₙ(16) = 2.773The logarithmic expression to calculate is given aslogₙ(1/63)Express 1/63 as 1/7 * 1/9So, we have the following representationlogₙ(1/63) = logₙ(1/7 * 1/9)Apply the product of logarithmThis giveslogₙ(1/63) = logₙ(1/7) + logₙ(1/9)Apply the exponent of logarithmThis giveslogₙ(1/63) = -logₙ(7) - logₙ(9)Substitute logₙ(7) = 1.946 and logₙ(9) = 2.197 in logₙ(1/63) = -logₙ(7) - logₙ(9)logₙ(1/63) = -1.946 - 2.197Evaluatelogₙ(1/63) = -4.143Hence, the value of the logarithmic expression is -4.143Read more about logarithm athttps://brainly.com/question/27451724#SPJ1