What is the pH of a solution prepared by adding 25.0 mL of 0.199 M ammonia to 25 mL of 0.199 M hydrochloric acid solution?

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The pH of a solution prepared by adding 25.0 mL of 0.199 M ammonia to 25 mL of 0.199 M hydrochloric acid solution is less than 7.What is the pH of a solution?The pH of a solution is calculated as follows;pH = - log ([H⁺])Also, pH = 14 - pOHThe pH of the solution is determined as follows;Moles of HCl = 0.199 M * 25 mL * 1L/1000 mLmoles of acid = 0.004975 molesMoles of NH₃ = 0.199 M * 25 mL * 1L/1000 mLmoles of NH₃ = 0.004975 moles0.004975 moles of HCl reacts with 0.004975 moles of NH₃ Since NH₃ is a weak acid, the pH of the solution is slightly lower than 7.Learn more about pH at: https://brainly.com/question/22390063#SPJ1