At a certain temperature, the solubility of aluminum hydroxide is (8.70x10^-13) M. What is the Ksp at this temperature?

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The solubility product (Ksp) at the given temperature is 2.27×10⁻²⁴ How do I determine the solubility product (Ksp)?We'll begin by writing the dissociation equation of aluminum hydroxide, Al(OH)₃. This is shown below:Al(OH)₃(aq) <==> Al³⁺(aq) + 3OH⁻(aq) Finally, we shall determine the solubility product (Ksp). This is illustarted below:Concentration of Al(OH)₃ = 8.70×10⁻¹³ MConcentration of Al³⁺ = 8.70×10⁻¹³ MConcentration of OH⁻ = 3 × 8.70×10⁻¹³ = 2.61×10⁻¹² MSolubility product (Ksp) =? Ksp = [Al³⁺] × [OH⁻] Ksp = 8.70×10⁻¹³ × 2.61×10⁻¹²Ksp = 2.27×10⁻²⁴Thus, we can coonclude that the solubility product (Ksp) is 2.27×10⁻²⁴ Learn more about solubility of product:https://brainly.com/question/4530083#SPJ1