A pumpkin is dropped from the top of a Cilk Fm broadcasting tower. What is the pumpkin's velocity 3.00 s later?

The velocity of the pumpkin 3.0 seconds after it was dropped is 29.4m/s. What is the pumpkins velocity after 3.0 seconds?The formula for the first equation of motion is expressed as;v = u + gtWhere v is final velocity, u is initial velocity, g is acceleration due to gravity ( g = 9.8m/s² ) and t is time elapsed.Given the data in the question;Since the pumpkin was initially at rest before it was dropped.Initial velocity u = 0Elapsed time t = 3.0s Velocity after 3 second v = ?To determine the velocity of the pumpkin after 3 seconds, plug the given values into the above equation of motion.v = u + gtv = 0 + ( 9.8m/s² × 3.0s )v = 9.8m/s² × 3.0s v = 29.4 m/sTherefore, the final velocity is 29.4 meter per seconds.Learn more about Equations of Motion here: brainly.com/question/18486505#SPJ1