How many grams of sodium iodide, Nal, must be used to produce 90.2 g of iodine, 1₂?
mass:
g Nal

300 grams of sodium iodide, Nal, must be used to produce 90.2 g of iodine, I₂ Sodium iodide is the ionic compound formed from the chemical reaction of sodium metal and iodine Here given data isI₂ has the molar mass = 253.8g/molSo how many moles of I₂ we want to produce = 90.2 g I₂ ×1mol I₂ /253.8g/mol = 0.35 mole of I₂ Then the conversion of NaI to I₂ are 2 NaI → 2Na + I₂ 0.35 mole of I₂ × 2 mole of NaI/mole of I₂ = 2 mole of NaI are needed covert this value into gram2 mole of NaI ×150. g NaI / mole NaI = 300 gram NaI would be neededKnow more about gramhttps://brainly.com/question/6579020#SPJ1