What is the slope-intercept form of the equation of the line shown in the graph?

The equation in slope intercept form is y= (-3/4)x + 95 .Linear FunctionAn equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=x+4. Where:m= the slope. It can be calculated for Δy/Δx.b= the constant term that represents the y-intercept.For the given example: m=1 and b=4.It is important to inform that the standard form for the linear equation can be called slope-intercept form.For writing a linear equation, you need two points. From the given graph, it is possible to extract some points, such as: (20,80), (60,50).Then, you should replace the known points in the slope-intercept form (y=mx+b).For the point (20,80),  you can write  80=m*20+b. And for the point (60,50), you can write 50=m*60+bThus, you have:80=20m+b   (1)50= 60m +b (2)For solving the previous system, you have to multiply the equation 1 by -1. Thus,-80=-20m-b   (1)50= 60m +b (2)After that, sum equations 1 and 2.-80+50 = -20m+60m-30=40mm=-30/40m=-3/4Now, you have y= (-3/4)*x+b.For finding coefficient b, you should use one of the given points. For example (20,80).y= (-3/4)*x+b for (20,80)80 = -3/4*(20) +b80= - 60/4+bb=80 + 60/4b=(320+60)/4b=380/4b=95Therefore, the equation in slope intercept form is y= (-3/4)*x + 95 . See the attached image.Read more about the linear equations here:brainly.com/question/2030026#SPJ1