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Triangles ABD and CBD are shown. Triangle A C D is divided into two smaller triangles which are triangle A B D and D B C which share a common side B D. Point B lies on segment A C. Segment A B is congruent to segment B C. If m∠ABD = 100°, what is the relationship between AD and CD?

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Answer:AB > BCStep-by-step explanation:The relationship between segments AB and BC is AB > BCHow to determine the relationship between the triangles?The triangles are given asMain triangle: Triangle ABCSmaller triangles: Triangle ADB and Triangle DBCThe figure (not drawn to scale) that illustrates the above triangles is added as an attachmentFrom the question, we understand that:Angle ADB = 110The above means thatAngle CDB + Angle ADB = 180 -- Sum of angles in a triangleSo, we haveAngle CDB + 110 = 180Evaluate the like termsAngle CDB = 70So, we haveAngle CDB = 70 and Angle ADB = 110Given that segments AD and CD are congruent, it means that the larger the angle, the larger the sideSo, we haveAB opposites ADB and BC opposites ACDWhich gives us the answer:AB > BC

Suggested Answer

Answer:they are congruent angles Step-by-step explanation:look at image