4-9×2^x+2+1=0. Please help me to solve the question please

Answer:x=[tex]log_{2} 7/9[/tex]Step-by-step explanation:4-9×2^x+2+1=04-9×2^x+3=04+3-9×2^x=07-9×2^x=07-7-9×2^x=0-7-9×2^x=-79×2^x=79×2^x/9=7/92^x=7/9[tex]log_{2} 2^x[/tex]=[tex]log_{2} 7/9[/tex]x=[tex]log_{2} 7/9[/tex]