calculate the density of 1mole of oxygen ata pressure of 4×10^-4Nm^-2 and a temprature of 273.2°K

The density of 1 mole of oxygen at a pressure of 4×10⁻⁴ Nm⁻² and a temprature of 273.2 K is 2.82×10⁻⁶ g/m³How to determine the density of oxygen We'll begin by obtaining the volume of the oxygen. This can be obtained as follow:Number of mole (n) = 1 molePressure (P) = 4×10⁻⁴ Nm⁻²Temperature (T) = 273.2 K Gas constant (R) = 8.314 m³Nm⁻²/KmolVolume = ?PV = nRT Divide both sides by PV = nRT / PV = (1 × 8.314 × 273.2) / 4×10⁻⁴V = 5678462 m³Finally, we shall determine the density of the oxygen. This can be obtained as follow: Mass of 1 mole of oxygen = 16 gVolume of 1 mole of oxygen = 5678462 m³Density of oxygen =?Density = mass / volumeDensity of oxygen = 16 / 5678462Density of oxygen = 2.82×10⁻⁶ g/m³Learn more about density:https://brainly.com/question/952755 #SPJ1