The distance (D) that a spring is stretched by a hanging object varies directly as the
weight (W) of the object. If a 6-kg object stretches a spring 29 cm, how far will a 25- kg weight stretch the spring?
Pls help asap! Tysm if u do!

The 25 Kg weight will stretch the spring 120.84 cm . In the question , it is given that the distance(D) that spring  stretches by hanging objects vary directly to the weight(W) of the object . which means D ∝ Wto remove the proportionality sign , we write the constant k So, D = k × W  ,where k is the constant of proportionality given that 6 Kg weight stretches the spring 29 cm So, 29 = k * 6k = 29/6to find the stretch for 25 Kg weight D = (29/6)*25D = 120.84 cm Therefore ,The 25 Kg weight will stretch the spring 120.84 cm . Learn more about Distance herehttps://brainly.com/question/5056426#SPJ1