Trevor and Michael are hosting a banquet. They plan to spend $400, plus or minus $50, at a cost of $25 per guest. Solve |25x-400| = 50 to find the maximum and minimum number of guests. If there can be up to 7 guests at each table, what is the minimum number of tables Trevor and Michael should reserve so that every guest has a seat?

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Answer:to find the max number of guests:25x-400 = 5025x = 50 + 40025x + 450then dividex = 450/25x = 18to find the min number of guests:25x = 400 - 5025x = 350then dividex = 350/25x = 14Minimum number of tables reserved: is dividing the max/7 per tablex = 18/7x = 3Step-by-step explanation: