Which equation represents a line which is perpendicular to the line y=7/6x-8

The equation of a line that is perpendicular to y = 7 / 6 x - 8 is y = -6 / 7 x + 8.How to find the equation of a line?The equation of a line can be represented in different form such as standard form, general form, slope intercept form and point slope form. The lines that are perpendicular to each other will have the products of their slopes as negative 1.Therefore, let express the equation in slope intercept form. y = mx + bwherem = slopeb = y-interceptTherefore,y = 7 / 6 x - 8The slope of the equation is 7 / 6. Therefore, let's find the equation of the line that is perpendicular to y = 7 / 6 x - 8.m₁m₂ = -17 / 6 m₂ = -1cross multiply7m₂ = -6m₂ = - 6 / 7Hence, the equation of the line perpendicular to y = 7/6x - 8 should have the slope as - 6 / 7.Hence, the equation can be y = -6 / 7 x + 8.learn more on equation here: https://brainly.com/question/11930347#SPJ1