Trevor and Michael are hosting a banquet. They plan to spend $400, plus or minus $50, at a cost of $25 per guest. Solve |25x-400| = 50 to find the maximum and minimum number of guests. If there can be up to 7 guests at each table, what is the minimum number of tables Trevor and Michael should reserve so that every guest has a seat?

1. The maximum and the minimum number of guests that Trevor and Michael should host at the banquet are 18 and 14, respectively.2. The minimum number of tables that Trevor and Michael will need for the banquet is 2.How are the numbers determined?We can employ the mathematical operations of addition, multiplication, division, and subtraction to determine the numbers.Since the budget is limited to $450 or less, we can compute the maximum and the minimum number of guests for the event, using division operation.Total budget for the banquet = $400 ± $50Cost per guest = $25Maximum number of guests to expect = 18 ($450/$25)Minimum number of guests to expect = 14 ($350/$25)The number of guests a table can accommodate = 7The minimum number of tables to use for the banquet = 2 (14/7)The maximum number of tables to use = 3 (18/7)Thus, using division operation, Trevor and Michael should expect to host between 14 and 18 guests at the banquet.Learn more about mathematical operations at https://brainly.com/question/20628271#SPJ1