Find the equation of a line parallel to 5x+3y=−21 that passes through the point (-9,-3)

To find: Equation of line parallel to 5x + 3y = -21 and passes through the point (-9, -3)Solving the given 5x + 3y = -21 for 3y yields  3y = -5x - 21.  Dividing all three terms by 3, we get:y = (-5/3)x - 7, indicating that the given line has slope -5/3.The slope of a line perpendicular to this y = (-5/3)x - 7 is 3/5, the negative reciprocal of -5/3.Start with y = mx + b Substitute -3 for y, -9 for x, and 3/5 for m We get,-3 = (3/5) (-9)  + b∴  b   = 5/9Thus, the equation is y = (3/5)x + 5/9 is the required equation of a line parallel to 5x+3y=−21 that passes through the point (-9,-3)Learn More about Coordinates geometry:https://brainly.com/question/11015532