A skier (m = 100 kg) is on level ground with a coefficient of kinetic friction of 0.05 m
moving at a speed of 100m/s. Calculate the distance the skier will go before they stop.
Use conservation of energy.

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The distance the skier will go before they stop is 10193.68m.Given ; Mass =100kgcoefficient of kinetic friction μ=0.05mu=100m/sv=0μg=a a= μg=0.05 x 9.81=0.4905 m/s²v²-u²=2as[v²-u²]/2a= s-100²/2(0.4905)s=10193.68m (neglecting the negative sign)To understand more about the coefficient of kinetic friction:-  https://brainly.com/question/15072984#SPJ1