What is the gravitational force acting on a 70.0 kg object standing on the Earth’s surface?
The radius of the earth is 6.371 x 106 m and the mass is 5.972 x 1024 kg.

The gravitational force acting on a 70.0 kg object standing on the Earth’s surface is 687.37NWhat is gravitational force ?A mass attracts a mass; the amount of the gravitational force is directly proportional to the masses of the two items and inversely proportional to the square of the distance between the two objects. Gravitational force is an attractive force that exists between all objects with mass.The square of the distance between two things has an inverse relationship with the force of gravity, which depends directly on the masses of the two items. Accordingly, the force of gravity increases with mass but decreases as object distance increases.F = G (M*m) /r2F =  6.674×10−11 * 5.972*10^24*70/ (6.371*10^6)^2   = 687.37NF = gravitational forceG = gravitational constantm = mass of the bodyM = mass of the earthr = distance between themTo know about gravitational force from the linkhttps://brainly.com/question/25624188#SPJ1