A cannon fires a cannon ball vertically into the air. Find the initial velocity if the cannon ball reached the height of 4.75 meters

The initial velocity of the cannon ball when it reached a height of 4.75 m is 9.65 m/s.Velocity- The rate of change of displacement is the definition of velocity.The formula below is used to determine the cannon ball's initial velocity.Formula:v² = u²+2gH......... Equation 1Where:v = Final velocityu = Initial velocityH = Heightg = Acceleration due to gravity.From the question,Given:v = 0 m/s (At the maximum height)H = 4.75 mg = 9.8 m/sSubstitute these values into equation 10² = u²+2×9.8×4.75u² = 93.1u = √(93.1)u = 9.65 m/sHence, the initial velocity of the cannonball is 9.65 m/s.Know more about velocity at: brainly.com/question/24739297