find the equation of a line that is equidistant from the points (2,4) and (-4,6)

The equation of a line is y = 5x - 6What is Equation of line ?A straight line's general equation is y = mx + b, where m denotes the gradient or slope and y = b denotes the point at which the line crosses the y-axis. On the y-axis, this value b is referred to as the intercept.The given points are (2, 4) and (-4, 6)The equation of line is given ,y = mx + bwhere, m = slopeb = y - intercept To find slope , we have formulaslope (m) = (y2 - y1) / (x2 - x1)let, (x1, x2) = (2, 4) and(y2, y1) = (-4, 6)Now, put the values in slope formula,m = ( 6 - (-4) ) / ( 4 - 2)m = (6 + 4) / 2m = 10 / 2m = 5We get slope, now find y-intercept i,e, 'b'y = 5x + bso take any point to find 'b'Let's take the point (2, 4) which is (x, y) so now put the (x, y) and find 'b'.4 = 5 * 2 + b4 = 10 + bb = 4 - 10b = -6so, now put the values of slope and y-intercept in equation of line i.e,        y = mx + by = 5x - 6Hence, the equation of a line is y = 5x - 6To read more about Equation of line.https://brainly.com/question/18831322#SPJ1