Can you please help me in this question.​

Answer:k = - 6 , c = 8Step-by-step explanation:f(x) = x² + kx + cgiven f(2) = 0 , substitute (2, 0 ) into f(x)0 = 2² + 2k + c0 = 4 + 2k + c ( subtract 4 from both sides )- 4 = 2k + c → (1)given f(- 3) = 35 , substitute (- 3, 35 ) into f(x)35 = (- 3)² - 3k + c35 = 9 - 3k + c ( subtract 9 from both sides )26 = - 3k + c → (2)subtract (2) from (1) term by term to eliminate c- 4 - 26 = 2k - (- 3k) + (c - c)- 30 = 2k + 3k- 30 = 5k ( divide both sides by 5 )- 6 = ksubstitute k = - 6 into (1) and solve for c- 4 = 2(- 6) + c- 4 = - 12 + c ( add 12 to both sides )8 = cthenk = - 6 and c = 8