A chemical company makes two brands of antifreeze. The first brand is 70% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 50 gallons of a mixture that contains 75% pure antifreeze, how many gallons of each brand of antifreeze must be used?

Answer:See below Step-by-step explanation:Final amount of pure antifreeze =   .75 (50) amount of 70 % that is pure antifreeze =  .70 xamount of 95 % that is pure antifreeze = .95 (50-x) ingredients in  =  ingredients out .70x     +    .95 (50-x)       = .75 (50) x = 40 gal    this is the amount of 70 %     then 95 % = 50 - 40 = 10 gal