Using the principle of conservation of mechanical energy, calculate the maximum height achieved by a 7 N ball tossed vertically upward with an initial velocity of 10 m/s.

Explanation:Given thatThe weight of a ball, [tex]W=7\ N[/tex]Initial velocity of the ball, [tex]v=10\ m/s[/tex]The principle of conservation of mechanical energy states that, the total energy of a system remains conserved. The mathematical form of the principle of conservation of mechanical energy is :[tex]\dfrac{1}{2}mv^2=mgh[/tex]Wherem is the mass of the objectv is the velocityh is the height Using the conservation of energy,[tex]\dfrac{1}{2}mv^2=mgh\\\\\dfrac{1}{2}v^2=gh[/tex]Solving for h,[tex]h=\dfrac{v^2}{2g}[/tex]Put all the values,[tex]h=\dfrac{(10)^2}{2\times 9.8}\\\\h=5.10\ m[/tex]Answer:The maximum height achieved by the ball is [tex]5.1\ m[/tex].Reference:
brainly.com/question/20971995

Because mechanical energy is conserved, potential energy due to gravity will equal the kinetic energy of the used to throw the ball. This is represented by mgh=.5mv^21. Divide both sides of the equation by m to ignore mass. The new equation will be gh=.5v^22. Substitute values into the equation: 9.8h=(.5)(10^2)--> 9.8h=503. Divide 50 by 9.8 to get h=5.102m