A current of 3.60A flows for 15.3s through a conductor. Calculate the number of electrons that pass through a point in the conductor in this time

3.60 A = 3.60 coulombs of charge per second(3.60 Coul/sec) x (15.3 sec) = 55.08 coulombs of charge1 coulomb of charge is carried by 6.25 x 10^18 electronsNumber of electrons =                (55.08 Coul) x (6.25 x 10^18 e/coul) = 3.4425 x 10^20 electrons

Answer: 3.44 x 10^20