Calculate the power in kilowatts required to lift a 500 kg mass 12 meters in one second

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Accepted Answer

The weight of the load is (mass) x (gravity).The work done to lift it is (weight) x (distance) = (mass) x (gravity) x (distance) The power is (work)/(time) =                (mass) x (gravity) x (distance) / (time)  =                 (500 kg) x (9.8 m/s²) x (12 m) / (1 sec) =                 (500 x 9.8 x 12 / 1) (kg-m / sec²) (m) / (sec) =                  (500 x 9.8 x 12 / 1)    newton  -  meter / sec =                   (500 x 9.8 x 12 / 1)             joule        /  sec =                                  58,800    watts                         =       58.8 kW                         =      about  78.8 horsepower     

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