how fast will a cart be moving if a force of 200 N is applied to a 50 kg cart for 10 sec?

Acceleration = (force) / (mass)If there is no friction . . .Acceleration = (200N) / (50 kg) = 4m/s²Change in speed = (acceleration) x (time) = (4 m/s²) x (10 sec) = 40 m/sFinal speed = (speed of the cart before the force began) + (40 m/s more)(That's about 89 mph faster than the cart was moving before the force started.)

I'm assuming that the cart starts from rest.Initial velocity (vi): 0 m/sFinal velocity (vf): ?Acceleration (a): ?Force (F): 200 NMass (m): 50 kgTime (t): 10 sF= ma200 N= (50kg)(a)a= +4 m/s^2a= (vf-vi)/t+4 m/s^2= (vf - 0m/s)/10svf= 40 m/sAnswer: the cart will be moving 40 m/s.