a man is pulling a block with a mass of 6.2kg across a horizontal surface and accelerates the block at a rate of 0.50m/s.the coefficient of kinetic friction between the block and the surface is 0.24. what is the magnitude with which the man pulls?

Answer:17.68 NExplanation:mass of block, m = 6.2 kg acceleration, a = 0.5 m/s^2 coefficient of friction, μ = 0.24 Net force - mass x acceleration F - f = ma where, F is the pulling force, f is the friction force and a be the acceleration F - μ mg = ma F - 0.24 x 6.2 x 9.8 = 6.2 x 0.5 F - 14.58 = 3.1 F = 17.68 NThus, the pulling force is 17.68 N.

mg = 6.2 x 9.81 = 60.822

This is also normal force.

Coefficient of friction times normal force is the force due to friction:
60.822 x 0.24 = 14.6N

F = MA so F(your force) - F(friction) = 6.2 x 0.5
= 3.1
Your answer is 3.1+ 14.6

I hope this is correct though I might be wrong.