Suggested Answer
You can use the conservation of energy to solve this problem. PE=KE pe=kemgh=(1\2)mv^2cancel out the mgh=(1\2)v^22gh=v^2√(2gh)=v√(2*9.81*5.40)=VV=10.2931 m/s Hope that helps.:)
You can use the conservation of energy to solve this problem. PE=KE pe=kemgh=(1\2)mv^2cancel out the mgh=(1\2)v^22gh=v^2√(2gh)=v√(2*9.81*5.40)=VV=10.2931 m/s Hope that helps.:)