An aircraft on it's take-off run has a steady acceleration of 3m/s^2. How much velocity does it gain 10 seconds?

Acceleration measures how fast the speed changes over time.So, over 10s, the aircraft's speed changes by 3[tex] \frac{m}{ s^{2} } [/tex] * 10sSo, the change is 30[tex] \frac{m}{s} [/tex]Note that the one of the second units cancels out in the answer.

To solve this, let's use the formula a=(v''-v')÷(t)3=(v''-0)÷(10)3=v÷10Now isolate for velocityv"=(3)(10)v"=30 m/s!