a 6-kg and a 4-kg ball are acted on by forces of equal size. if the large ball accelerates at 2 m/s2 what acceleration will the small ball undergo

To answer this question, we need to find the force acting on the two objects.f=maf=(6)(2)f=12 newtonsSo, now we can determine the acceleration of the second object using the same formula!f=ma12=(4)a3=aSo the acceleration of the smaller object is 3 meters per second squared!

It would be 30 meters.