We want to find how much charge is on the electrons in a nickel coin. Follow this method. A nickel coin has a mass of about 5.7 g.
a. Find the number of atoms in a nickel coin. Each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g. Answer in units of atoms.
b. Find the number of electrons in the coin. Each nickel atom has 28 electrons/atom. Answer in units of electrons.
c. Find the magnitude of the charge of all these electrons. Answer in units of C.

The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.The magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.Given information-The mass of the nickel coin is 5.7 g.A)  The number of atoms in a nickel coin.How to find number of atom in metal?The number of atoms in a metal the product of weight of the atom of the metal and Avagardo's number divided by atomic mass.As each mole (6.02 × 10^23 atoms) has a mass of about 57.9 g. Thus the number of atom in a nickel coin with mass 5.7 kg,[tex]n=\dfrac{5.7}{57.9} \times6.02\times 10^{23}[/tex][tex]n=5.93\times 10^{22}[/tex]Hence  the number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.B) Number of electrons in the coin. As each nickel atom has 28 electrons/atom and total number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms. Thus number of electrons in the coin in nickel coin is,[tex]q=5.93\times10^{22}\times28\\q=1.66\times 10^{24}[/tex]Hence the number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.C) The magnitude of the charge of all these electrons-Magnitude of the each electron, is [tex]1.6\times10^{-19}[/tex]. Thus the magnitude of the charge of all these electrons is,[tex]e=1.66\times 10^{24}\times1.6\times10^{-19}\\e=2.656\times10^{5}[/tex]Thus the magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.Hence,The number of atom in a nickel coin with mass 5.7 kg is [tex]5.93\times 10^{22}[/tex] atoms.The number of electrons in nickel coin is [tex]1.66\times 10^{24}[/tex] atoms.The magnitude of the charge of all these electrons is  [tex]e=2.656\times10^{5}[/tex] C.Learn more about the atomic number here;https://brainly.com/question/2099804

5.6x10e22 atomsHope I helped, and good luck!