Accepted Answer
[tex]KE = \frac{1}{2}mv^{2} \\ v = \sqrt{ \frac{2KE}{m} } \\ v = \sqrt{ \frac{2*8J}{1kg} } \\ v = 4m/s[/tex]Therefore, the ball has a velocity of 4m/s.
Related Question in Physics
[tex]KE = \frac{1}{2}mv^{2} \\ v = \sqrt{ \frac{2KE}{m} } \\ v = \sqrt{ \frac{2*8J}{1kg} } \\ v = 4m/s[/tex]Therefore, the ball has a velocity of 4m/s.