the amount of charge that moves through the filament of a lightbulb in 2.00 s is 2.67 C. what is the current of the lightbulb?

The electric "current" in a conductor is the rate at which charge flows through it.Current = (charge) / (time)Current = (2.67 Coulombs) / (2 seconds)  =                  1.335 Coulombs per second =                            1.335 Amperes