please help How much heat does it take to raise the temperature of 9.0 kg of wood from 12C to 97C? The specific heat of wood is 1.68 kJ/(kgC). Use Q = mc(Tf - Ti). A. 760 kJ B. 1300 kJ C. 180 kJ D. 1500 kJ

Answer:[tex]Q = 1300 kJ[/tex]Explanation:As we know that heat require to change the temperature of the object is given as[tex]Q = mC \Delta T[/tex]here we know thatm = mass = 9 kgC = 1.68 kJ/kg[tex]\Delta T = 97 - 12[/tex][tex]\Delta T = 85 degree C[/tex]now from above formula we will have[tex]Q = 9\times 1.68 \times 10^3 \times 85[/tex][tex]Q = 1300 kJ[/tex]

Q=mc(Tf-Ti)   = (9Kg)(1.68 KJ/KgC)(97-12)   = 1285.2 KJ   ~ 1300 KJ