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I need to find the zeros of the function:f(x)=2x^2-5x-3

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[tex]2x^2-5x-3=0\\
2x^2-2x-3x-3=0\\
2x(x+1)-3(x+1)=0\\
(2x-3)(x+1)=0\\
x=\frac{3}{2} \vee x=-1[/tex]

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