A 1200 kg vehicle initially travelling at 50. km/h experiences an air resistance of 5000 N and road friction of 2200 N. The wheels deliver a force of 7500 N to the vehicle. What is its acceleration?

The forces on the car are:-- 7,500 N forward, from the engine-- 5,000 N backwards, from air resistance-- 2,200 N backwards, from road frictionThe net force on the car is (+7,500 - 5,000 - 2,200) = 300 N forward .Newton said: Force = (mass) x (acceleration)Divide each side by (mass) :Acceleration = (force) / (mass)Acceleration = (300 N) / (1,200 kg) = 0.25 m/s² forward.Notice the big red herring at the beginning of the question:It's nice to know that the vehicle starts out traveling at 50 km/hr,but in order to answer this question, we honestly don't care !