Accepted Answer
[tex]y=x^2-1[/tex][tex]0=x^2-1[/tex][tex]0=(x+1)(x-1)[/tex][tex]x+1=0[/tex][tex]x=-1[/tex][tex]x-1=0[/tex][tex]x=1[/tex][tex]zeros:-1,1[/tex]
Accepted Answer
y = x² - 1I can find the zeros from a graph, but that won't help you any, because I'm not about to draw the graph and then post it here. y = (x + 1) (x - 1)y = 0 when x = +1 or x = -1.