a hydrogen-filled balloon was ignited and 1.60g of hydrogen reacted with 12.8g of oxygen. how many grams of water vapor were formed? (assume that water vapor is the only product.)could you help me with this one:) ?

2H2 + O2 ---> 2H2O1 mole of H2 = 2g1 mole of O2 = 32g1 mole of H2O = 18gaccording to the reaction:2*2g H2---------------32g O21,6g H2----------------- x g O2x = 12,8g O2so reaction is stechiometric32g O2---------------- 2*18g H2O12,8g O2 -------------- xx = 14,4g H2Oanswer: 14,4g of water vapour