Two numbers add to 251 and the second is 41 bigger then the first. what are the two numbers?

[tex]\left\{\begin{array}{ccc}x+y=251\\y=x+41\end{array}\right\\\\substitute:\\\\x+x+41=251\\2x+41=251\ \ \ \ /-41\\2x=210\ \ \ /:2\\x=105\\\\y=105+41=146\\\\Answer:105\ and\ 146.[/tex]

146 dan 105Further explanationGiven:Two numbers add to 251 and the second is 41 bigger than the first.Question:What are the two numbers?The Process:Let the first number we call x, and the second number is y.Two numbers add to 251, We arrange it as Equation-1: [tex]\boxed{ \ x + y = 251 \ }[/tex]The second is 41 bigger than the first. We arrange it as Equation-2:[tex]\boxed{ \ x = y + 41 \ } \ or \ \boxed{ \ x - y = 41 \ }[/tex]Let us solve the two equations above by eliminating the same variable. With the addition process, it appears that the variable y will be eliminated.x + y = 251x - y = 41-------------- ( + )2x = 292Divide by two on both sides.x = 146The final step is to determine the variable y with the substitution of the value x into one of the two equations above. We choose Equation-1.x = 146 → 146 + y = 251y = 251 - 146y = 105.Thus, the two numbers are 146 and 105.Learn moreHow many solutions exist for the given equation?  https://brainly.com/question/11306893#
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