A man is carrying a trolley of mass 6kg and having K.E. of 40 J . Calculate its velocity with which he is running .

The formula to find kinetic energy is -[tex]K.E. = \frac{1}{2}*m* v^{2} [/tex]Where,[tex]m = mass[/tex]and[tex]v = velocity[/tex]So, putting the values in the formula we get -[tex]40 = \frac{1}{2} *6*v^{2} [/tex][tex] \frac{40}{3} = v^{2} [/tex][tex] \sqrt \frac{40}{3} = 3.6514 m/s[/tex]

As we know that K.E = 1/2 mv² so by arranging it K.E ×2÷6 = v²now by putting valuesv²=13.33 m²/s²sov= 3.65 m/s....