An antacid tablet containing 0.50 g of NaHCO3 is dissolved in 250 mL of water. What is the molar concentration of NaHCO3 in the solution?

1 mole of NaHCO3 = 84g1 mole of NaHCO3--------------84gx moles of NaHCO3----------0,50gx = 0,00595 moles of NaHCO30,00595 moles of NaHCO3----------in--------250mlx moles of NaHCO3-------------------in-----------1000mlx = 0,0238 moles of NaHCO3answer: the molar concentration of NaHCO3 is 0,0238mol/l

Hello!An antacid tablet containing 0.50 g of NaHCO3 is dissolved in 250 mL of water. What is the molar concentration of NaHCO3 in the solution ?We have the following data:M (Molar Concentration or Molarity) = ? (in mol/L)m (mass) = 0.50 gV (volume) = 250 mL → 0.25 LMM (Molar Mass of NaHCO3)Na = 1*(23u) = 23 uH = 1*(1u) = 1 uC = 1*(12u) = 12 uO = 3*(16u) = 48 u-------------------------------MM (Molar Mass of NaHCO3) = 23 + 1 + 12 + 48 = 84 g/molWe apply the data found to the formula of molar Concentration or Molarity, let's see:[tex]M = \dfrac{m}{MM*V}[/tex][tex]M = \dfrac{0.50}{84*0.25}[/tex][tex]M = \dfrac{0.50}{21}[/tex][tex]M = 0.023809... \to \boxed{\boxed{M \approx 0.024\:mol/L}}\:\:\:\:\:\:\bf\purple{\checkmark}[/tex]Answer:  The Molar Concentration is approximately 0.024 mol/L________________________[tex]\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}[/tex]