Accepted Answer
I'll tell you how I look at this, although I may be missing something important.Position = x(t) = 0.5 sin(pt + p/3)Speed = position' = x'(t) = 0.5 p cos(pt + p/3)Acceleration = speed' = position ' ' = x ' '(t) = -0.5 p² sin(pt + p/3)At (t = 1.0),x ' '(t) = -0.5 p² sin( 4/3 p )In order to evaluate this, don't I still have to know what 'p' is ? ?I don't think it can be evaluated with the information given in the question.