Accepted Answer
[tex]f(x)=2x-3\\\\y=2x-3\\\\-2x=-y-3\ \ \ \ /:(-2)\\\\x=\frac{1}{2}y+\frac{3}{2}\\\\f^{-1}(x)=\frac{1}{2}x+\frac{3}{2}[/tex]
Suggested Answer
f(x)=2x-3y=2x-3x=(y+3)/2f⁻¹(x) = (x+3) / 2
Related Question in Mathematics
[tex]f(x)=2x-3\\\\y=2x-3\\\\-2x=-y-3\ \ \ \ /:(-2)\\\\x=\frac{1}{2}y+\frac{3}{2}\\\\f^{-1}(x)=\frac{1}{2}x+\frac{3}{2}[/tex]
f(x)=2x-3y=2x-3x=(y+3)/2f⁻¹(x) = (x+3) / 2