The question that I'm having issues with is, "The complement of an angle, A, in degrees, is equal to one-sixth of the supplement of the angle, also in degrees.  Then A= "I know the answer is 72 degrees, but I don't know how to figure the problem out!

'Complement' = difference between an angle an 90 degrees.'Supplement' = difference between an angle and 180 degrees.Complement of A = 90 - ASupplement of A = 180 - AThe problem says that the complement is 1/6 of the supplement, right ?So      90 - A = (1/6) x (180 - A)Multiply each side of this equation by 6 :540 - 6 A = 180 - ASubtract 180 from each side:360 - 6 A = - AAdd 6A to each side :360 = 5 ADivide each side by 5 :A = 72°

[tex]90-A=\frac{180-A}{6}\\
540-6A=180-A\\
5A=360\\
A=72[/tex]