determine whether (5,6) is the solution for y=x+1

[tex](5,6)[/tex][tex]x=5 \\ y=6[/tex][tex]y=x+1[/tex][tex](6)=(5)+1[/tex][tex]6=6[/tex][tex]true[/tex]

Has your class not learned how to check an answer to see if it's correct ? ! ?Your equation is [ y = x + 1 ].You want to know whether (5, 6) is A solution to the equation.When you write (5, 6), that means "x=5 and y=6".So put those numbers into the equation in place of 'x' and 'y'and see if the equation is true after you do that.(y) = (x) + 1(6) = (5) + 1Do you see 5+1 on the right side.  That's 6.So the equation says " 6 = 6 " . . . a true statement.So (5, 6) is a solution of the equation.It's not THE solution.  There are an infinite number of solutionsto that equation.  (5, 6) is one of them.