A wire 2 m long, 0.1 mm in diameter and has resistance of 20 ohm. Calculate the resistivityof its material.

R=[tex] \frac{pL}{A} [/tex]R-resistancep-resistivity [Ohm*m]A-cross sectional areaL-lengthR=20 Ohml=2mA=[tex] \pi r^{2} [/tex]=[tex] \pi (0,01)^{2} =0,000314 cm^{2} [/tex]=0,314*[tex] 10^{-7} [/tex]m²p=[tex] \frac{R*A}{L} [/tex]p=[tex] \frac{20*0,314*10^{-7}}{2} [/tex]=0,000000314 Ohm*m