What's the value of X

[tex](x+1)^2 -(x-1)^2 = 32 \\ \\x^2+2x+1 -(x^2-2x+1)=32\\ \\x^2+2x+1-x^2+2x-1=32\\ \\ 4x =32\ \ / :4 \\ \\x=\frac{32}{4}\\ \\x=8 [/tex]

All the busy-work is on the left side.1). Take care of the (x+1)² . . .(x + 1)² = x² + 2x + 12).  Take care of the (x-1)² . . .(x - 1)² = x² - 2x + 1The problem says that (the first expression) minus (the second expression) is 32 .(x² + 2x + 1) - (x² - 2x + 1) = 32Can you handle this ?Only one more touchy point to take care of . . . removing the second parentheses.Since there's a negative sign before it, that changes the sign of everything inside:(x² + 2x + 1) PLUS (- x² + 2x - 1) = 32Now you can just erase all the parentheses:x² + 2x + 1   -  x² + 2x - 1 = 32Now I'm just going to write the things on the left side in a different order,without changing anything:x² - x²     + 2x + 2x        + 1 - 1 = 32Isn't that neat ? ! ?What you have now is:4x = 32Divide each side by 4 :x = 8Just watch how slick that works:(x + 1)² - (x - 1)² = ?(x + 1) = 9      (x - 1) = 7(9)² - (7)² = 81 - 49 = . . . . . . . . 32 !спасибоУдачи