Suggested Answer
[tex]4x^2 = 36 + 9y^2\\
\\
4x^2-9y^2=36\\
\\
\frac{4x^2}{36}-\frac{9y^2}{36}=\frac{36}{36}\\
\\
\boxed{\frac{x^2}{9}=\frac{y^2}{4}=1}[/tex]
[tex]4x^2 = 36 + 9y^2\\
\\
4x^2-9y^2=36\\
\\
\frac{4x^2}{36}-\frac{9y^2}{36}=\frac{36}{36}\\
\\
\boxed{\frac{x^2}{9}=\frac{y^2}{4}=1}[/tex]