Last one for the day :)Find the slope of the line

Line pass to points:  (-5;0) and (0;-5)So:[tex] \left|\begin{array}{ccc}x&y&1\\-5&0&1\\0&-5&1\end{array}\right|=0\\
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25+5y+5x=0\\
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5+y+x=0\\ y=-x-5\\
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slope=-1 \ \ \(coeficient \ of \ "x")[/tex]

For each unit of progress toward the right ... as 'x' increases ... the line drops one unit.Its slope is -1.