The slope of a line is -1/3 and the y-intercept is 10/3. What is the equation of the line written in general form?

[tex]Slope-intercept\ form:y=mx+b\\\\m-slpoe\\b-y-intercept\\\\y=-\frac{1}{3}x+\frac{10}{3}\\\\General\ form:Ax+By+C=0\\\\y=-\frac{1}{3}x+\frac{10}{3}\\\\\frac{1}{3}x+y-\frac{10}{3}=0\ \ \ \ /\cdot3\\\\x+3y-10=0[/tex]

In slope-intercept form:y = mx + bwhere:     m = slope = -1/3     b = y-intercept = 10/3y = (-1/3)x + 10/3However, you want the equation organized in general form, which is:Ax + By + C = 0This simply requires us to rearrange terms (starting from slope-intercept form):y = (-1/3)x + 10/3(moving all terms to the left)y - (-1/3)x - 10/3 = 0y + 1/3x - 10/3 = 01/3x + y - 10/3 = 0For general form:A = 1/3B = 1C = -10/3