sinxtanx=secx-cosx Please help me solve it

[tex]sinx.tanx=secx-cosx\\
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sinx.\frac{sinx}{cosx}=\frac{1}{cosx}-cosx\\
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\frac{sin^2x}{cosx}=\frac{1-cos^2x}{cosx}\\
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\frac{sin^2x}{cosx}=\frac{sin^2x}{cosx}[/tex]