Suggested Answer
[tex]1)\\ 3*4^0=3*1=3\\\\ 2)\\ a^{-b=(\frac{1}{a})^b}}\\
\frac{1}{4^{-2}}=\frac{1}{(\frac{1}{4})^2}=\frac{1}{\frac{1}{16}}=1*\frac{16}{1}=16[/tex]
[tex]1)\\ 3*4^0=3*1=3\\\\ 2)\\ a^{-b=(\frac{1}{a})^b}}\\
\frac{1}{4^{-2}}=\frac{1}{(\frac{1}{4})^2}=\frac{1}{\frac{1}{16}}=1*\frac{16}{1}=16[/tex]